Find the probability that a leap year chosen at random will contain 53 sundays. 1. 2/7 2. 3/7 3. 1/49 4. 1/7

Since, the total days in a leap year is 366 days.
Therefore,
             366/7=52Weeks+2days
It keeps already 52 sundays,mondays,etc.
then it have 2 days that may be 
{sunday,monday} , {monday,tuesday} , {tuesday,wednesday} ,....{saturday,sunday}

Then, the 2 possible chances out of 7.

hence, the probability:2/7.

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