Solving expression as below;
\(\begin{array}{c}{\log _3}{27^x} = {\log _3}{({3^3})^x}\\ = {\log _3}{3^3}^x\\ = 3x{\log _3}3\\ = 3x\left( 1 \right)\\ = 3x\end{array}\)
So, the expression has evaluated as.
\({\log _3}{27^x} = 3x\)
\(\begin{array}{c}{\log _3}{27^x} = {\log _3}{({3^3})^x}\\ = {\log _3}{3^3}^x\\ = 3x{\log _3}3\\ = 3x\left( 1 \right)\\ = 3x\end{array}\)
So, the expression has evaluated as.
\({\log _3}{27^x} = 3x\)